Easy way to parse JSON with JavaScript

When you use JSON.parse to parse JSON, you almost always need to make sure you pass in a JSON value, so you will end up having to use a try/catch block most of the time.

try {
  const content = JSON.parse(someValue)
} catch (e) {
  // Handle the error
}

Most of the time, you’ll want to set a default value when the parsing fails. So the code ends up looking like this:

let content
const defaultValue = {} // Change this to any other value

try {
  content = JSON.parse(json)
} catch (e) {
  content = defaultvalue
}

I think this process can be simplified so I created a helper function, parseJSON that lets you do these two things in a single line:

1. Specify the JSON content to parse.
2. And if that fails, specify a default value.

Using parseJSON

You can use parseJSON by first installing Splendid UI.

npm install splendidlabz

Then import it into your project:

import { parseJSON } from 'splendidlabz/utils'

Here’s how you can use parseJSON.

const value = parseJSON(json, defaultValue)

// If JSON is valid value will be === JSON data
// If JSON is invalid, value will be === defaultValue

parseJSON is equivalent to the code I just wrote above:

// Parse JSON lets you write these 7 lines of code in a single line
let content
const defaultValue = {}

try {
  content = JSON.parse(json)
} catch (e) {
  content = defaultvalue
}

Since parseJSON is a Vanilla JavaScript utility, you can use it anywhere — frontend JavaScript, Node, and even in frameworks!

That’s all you have to know about parseJSON!

Take it out for a spin and let me know what you think!

Further reading

• Splendid UI
• parseJSON documentation